Reversing a number

/*A program to print a given integer in reverse order and sum it with original */

#include<stdio.h>

int main()  /* use 'long' instead of 'int' if integer is a long integer */
{
    int n, reverse = 0,temp;
    printf("Enter a number to reverse\n");
    scanf("%d",&n);
    temp=n;
    while( n != 0 )
   {
      reverse = reverse * 10;
      reverse = reverse + n%10;
      n = n/10;
   }

    printf("Reverse of entered number is %d\n", reverse);
    printf("sum of original number %d and reversed number %d is %d\n",temp,reverse,temp+reverse);
    return 0;
}